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Description

Calculate [H+] for a 1.10×10-3 M aqueous solution of n-butyric acid (HC4H7O2Ka = 1.50×10-5).

Calculate the pH of the above solution.

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Explanation & Answer


HC4H7O2H+C4H7O2-
Initial1.10e-3 M00
Change-x+ x+x
Equilibrium1.10e-3 - xxx

Ka = 1.5e -5 = [H+][C4H7O2-] / [HC4H7O2]


1.5e-5 = x^2/ 1.1e-3 -x

x^2 = 1.65e-8 - 1.5e-5x

x^2 + 1.5e-5x - 1.65e-8 = 0

Solve via quadratic equation

x = 0.000121

pH = - log (0.000121) = 3.92


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