Description
A function is given. Determine the average rate of change of the function between the given values of the variable.
h(t) = t2 + 5t; t = −1, t = 2
af(z) = 5 − 4z2; z = −2, z = 0
f(x) = x3 − 5x2; x = 0, x = 10
f(x) = x + x4; x = −3, x = 5
f(x) = 5x2; x = 3, x = 3 + h
f(x) = 3 − x2; x = 6, x = 6 + h
Explanation & Answer
[4+5-(1-5)]/3 = 13/3
[5-(5-16)]/2 =8
[1000-500-0]/10 =50
[5+625+3-81]/8 = (633-81)/8 = 552/8 = 69
[5(3+h)^2-5(3)^2]/h = 5(9+6h+h^2-9)/h = 5*6+5h = 30+5h
[3-(6+h)^2-3+6^2]/h = -(36+12h+h^2-36)/h = -12-h
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