Description
ionic solid SrF2. When dissolved in pure water, its solubility is found to be 8.9×10-4 M.
Give the formula of the anion in this compound.
What is the concentration of this anion in a saturated solution of SrF2?
Determine the value of Ksp for SrF2.
Explanation & Answer
a) Formula of ion = F^-
b) concentration of anion
The solubility is 8.9×10^-4 M. For each mol of SrF2 that goes into solution, there will be two mols of F-.
= 8.9×10^-4 M * 2
= 1.8×10^-3 M
c) Ksp for SrF2
ksp = [Sr^2+] * [F-] ^ 2
= (8.9×10^-4 M) * (1.8×10^-3 M) ^2
= 2.8 ×10^-9
agrees in magnitude with literature value
Review
Review
24/7 Homework Help
Stuck on a homework question? Our verified tutors can answer all questions, from basic math to advanced rocket science!
Similar Content
Related Tags
The Old Man and the Sea
by Ernest Hemmingway
Homo Deus
by Yuval Noah Harari
Narrative of the Life of Frederick Douglass
by Frederick Douglass
The Joy Luck Club
by Amy Tan
Where'd You Go Bernadette
by Maria Semple
A Portrait of the Artist as a Young Man
by James Joyce
The House of the Seven Gables
by Nathaniel Hawthorne
Death Of A Salesmen
by Arthur Miller
The Mayor of Casterbridge
by Thomas Hardy