Find area under a curve between x=12 and x=24 for the equation [-(x-18)^2/2] 24

Anonymous
timer Asked: Mar 1st, 2015

Question description

For a Pre-Calc project (preparation for calculus I), it is about using two parabolas between x=12 and x=24, who intersect at y=6. Double the area under a curve in the question, and then subtract it from the area of an ellipse with this equation [(x-18)^2/36]+[(y-6)^2/36], so what is the difference in square units.

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