please help be specific fas fast please due

User Generated

ozbqr

Science

Description

1,,seclect conductor  or nonconductor

melted aluminum iodide 
solid sodium chloride 
oxygen dissolved in pure water 
pure liquid water 

2,,How many mL of a 8.00 M solution of nitric acid are required to prepare 350 mL of a 0.150 M solution? 

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Explanation & Answer

1.  melted aluminum iodide .............conductor
     solid sodium chloride.......................nonconductor 
     oxygen dissolved in pure water.......very very weak conductor (nonconductor
     pure liquid water...............................very very weak conductor (nonconductor)


2. use dilution eqn  (c1)(v1) = (c2)(v2)

solving for v2...

v2 = (c1)(v1)/(c2)

v2 = (0.150 M)(350 mL) / (8.00 M)

6.6 mL (with sigfigs in mind) 



Anonymous
I was having a hard time with this subject, and this was a great help.

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