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How many mL of 8.0 M HCl must you dilute with an appropriate volume of H2O to prepare a total volume of 410.0 mL of 2.0 M HCl?

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Explanation & Answer

M1=8

M2=2M

V2=410ml

V1=?

M1*V1=M2*V2

V1=M2*V2/M1

   =2*410/8

=102.5 ml



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