Please answer question below

User Generated

xryyl0719

Science

Description

User generated content is uploaded by users for the purposes of learning and should be used following Studypool's honor code & terms of service.

Explanation & Answer

623.1g/1329g = 

mass percent is thus 0.4681x100 = 46.81 % H2SO4. 

First, calculate the mass of solvent: mass of solvent = mass of solution – mass of H2SO4 = (density x volume) of solution – mass of H2SO4 = (1.329 kg/L x 1L) solution – 0.6231 kg of H2SO4 = 0.7059 kg of solvent 

mole of H2SO4=623.1/98.09=6.352 mol fraction

molarity=6.352/0.7059=8.998 m H2SO4

Molarity in Solution=6.352/1L Soln=6.352 M H2SO4




Anonymous
I was stuck on this subject and a friend recommended Studypool. I'm so glad I checked it out!

Studypool
4.7
Trustpilot
4.5
Sitejabber
4.4

Related Tags