# find temp of saturated solution by using the solubility vs temp table

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Find the value for the temperature of a saturated solution of NH4Cl at an approximate concentration of 7.5 M? Assuming X grams of solute/100 grams water 100 grams of water = 100.0 mL of water I was thinking i need to convert the 7.5 M = mol/L  by changing the 7.5 M NH4Cl to grams and 1 mol = 53.50g. I started dimensional analysis.. so i have 7.5 mol/L(top) = 1 mol(bottom) = 53.50 grams(top) = 100g H2O(bottom) = 100.0 mLH2O(top) = 1000mL(bottom) = 1L(top) but the every thing canceled except the liter that are both on top  Im lost i know i went wrong somewhere or Im completely wrong

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