Description
21.30 mL of 0.015M HCl is needed to titrate a 10.00mL saturated Ca(OH)2 solution at 25 degrees celsius. What is the Ksp of Ca(OH)2?
Explanation & Answer
The reaction equation is 2HCl (aq) + Ca(OH)2 (aq) => CaCl2 (aq) + 2H2O
The number of moles of HCl reacted: 0.015 mol/L * (21.30/1000) L = 3.195*10^{-4} mol
The number of moles of Ca(OH)2 reacted: 1.5975*10^{-4} mol (the ratio of the coefficients is 2:1).
The molar concentration of dissolved Ca(OH)2 was 1.5975*10^{-4} mol / (10.00/1000 L) = 0.01598 mol/L
When calcium hydroxide dissolves, Ca(OH)2 => Ca2+ + 2 OH- and Ksp = [Ca2+] * [OH-]^2,
where the concentrations are [Ca2+] = 0.01598; [OH-] = 2*0.01598 = 0.03196.
Finally, Ksp = 0.01598 * 0.03196^2 = 1.632 * 10^{-5}.
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