# 2sin2(3x)=11cos(3x 7) Given that 0≤x<360 This is what I need help with!

*label*Calculus

*timer*Asked: Mar 27th, 2015

**Question description**

2sin2(3x)=11cos(3x+7) Given that 0≤x<360 and Write the first three terms of an arithmetic sequence in which the thirty-first term is 34 and the forty-ninth term is -56.