Need help with Probability and Statistics

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Mathematics

Description

A and B are events with Pr[A] = 0.25, Pr[B] = 0.32, and Pr[A ∩ B] = 0.06.

Calculate . Pr(A l B')

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Explanation & Answer

OK, so we have:

P(A) = 0.25

P(B) = 0.32

P(A and B) = 0.06


So, P(A | B') = P(A given not B).

= ( P(A) - P(A and B) ) / ( 1 - P(B) )

= 0.19 / 0.68

= 0.2794


In other words, we're figuring out how much of A's probability occurs "outside" of B occuring (0.25-0.06 = 0.19); then dividing that by the whole probability of B not occurring (0.68). Drawing a Venn diagram will probably help you to visualise this if it's still a little tough to grasp!


Anonymous
Great study resource, helped me a lot.

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