Description
A sample of 49 observations is selected from a normal population. The sample mean is 61, and the population standard deviation is 6. Conduct the following test of hypothesis using the 0.10 significance level. |
H0: μ = 63 |
H1: μ ≠ 63 |
Explanation & Answer
t = (61-63)/(6/7) = -2*7/6 = -7/3 = -2.333
Tabular value for 1% (two tailed) is 1.6772 for 48 df
| t | =2.333 > 1.6772
we reject the null hypothesis.
And conclude that mean is not equal to 63