I've already figured half of this problem out but can not finish the second part

User Generated

RevaGx5

Mathematics

Description

A drug is eliminated from the body through urine. Suppose that for an initial dose of 50 milligrams, the amount A(t) in the body t hours later is given by A(t) = 50(0.8)t.

(a) Estimate the amount of the drug in the body 7 hours after the initial dose. (Round your answer to two decimal places.)
  mg

(b) What percentage of the drug still in the body is eliminated each hour?

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Explanation & Answer

Twenty percent is eliminated each hour, since only 80% of the previous hours drug remains each successive hour. Here is the proof:

 Hour1
2
3
4
5
6
7
Drug in Body
40
32
25.60
20.48
16.38
13.11
10.49
Drug Eliminated
 8
6.40
5.12
4.10
3.28
2.62
Percentage Eliminated From Previous Hour

20%
20%
20%
20%
20%
20%



Anonymous
This is great! Exactly what I wanted.

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