Description
like a flat, isotropic plat
10°C to the floor of a compartment 2.15m below. The mean emissivity is 0.41 and the floor is homogenous/flat plate at 35°C. What is the rate of heat transfer from the smoky layer to the floor?
Explanation & Answer
I believe the temperature is not 10 degree celsius and it is 510 degree celsius I will solve the question as 510 degree celsius
Heat transfer rate =. Emmisivity x Boltzmann constant x area x (temp 1 in Rankin) ^4 -temp 2 in Rankin^4
= 0.41 x 0.1713 x 10^ -8 x ( 385.5 x 10^ 10)
= 2707 BTU/hr or 2856 kJ/hr
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