Description
A. A beaker contains 400. mL of 0.160 M HNO3. What volume of 0.295 M KOH solution is needed to exactly neutralize the acid?
B.A beaker contains 35.0 mL of 0.200 M HCl solution. A few drops of phenolphthalein is added to the solution. How many milliliters of 0.700 M NaOH should be added to exactly neutralize the HCl solution in the beaker
Explanation & Answer
a) M1V1 = M2V2
400 x 0.160 = 0.295 x V(KOH)
V(KOH) = 216.94 mL
b) M1V1 = M2V2
35.0 x 0.2 = 0.7 V(HCl)
V(HCl) = 10 mL
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