Quadratic Function Fixed Points

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Xnvgyla859

Mathematics

Description

Give a quadratic function whose fixed points are x = −5 and x = 6.

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Explanation & Answer

Quadratic function is of the type Ax^2+Bx+C

we have x=-5  and x=6

therefore,

Quadratic function is

(x+5)(x-6)=0

solving,

x^2-6x+5x-30=0

x^2-x-30=0

is the required Quadratic function.


Anonymous
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