Description
Give a quadratic function whose fixed points are x = −5 and x = 6.
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Explanation & Answer
Quadratic function is of the type Ax^2+Bx+C
we have x=-5 and x=6
therefore,
Quadratic function is
(x+5)(x-6)=0
solving,
x^2-6x+5x-30=0
x^2-x-30=0
is the required Quadratic function.
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