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Explanation & Answer
s1² =√ (8250 - 8179.6)/10 = 7.04
s2² = √(8496 - 8000.9/10) = 8.71
s² = (7.04 + 8.71)/2 = 7.875
and s = 2.806
Now critical t value (18 df) at 90% confidence is 1.734
difference in means = 28.6 - 28.3 = 0.3
Hence confidence interval =( 0.3 -1.734* 2.806, 0.3 + 1.734*2.806)
= (-0.187, 0 .7.866)
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