Description
Water drives a waterwheel (or turbine) of radius R =3.0 m as shown in Fig. 11-33. The water enters at a speedv1 = 7.0 m/s andexits from the waterwheel at a speed v2 = 3.8m/s.
(a) If 85 kg of waterpasses through per second, what is the rate at which the waterdelivers angular momentum to the waterwheel?
kgm2/s2
(b) What is the torque the water applies to the waterwheel?
mN
(c) If the water causes the waterwheel to make one revolution every5.5 s, how much power is delivered to the wheel?
W
Explanation & Answer
a)mass of water=85 kg
Loss in the velocity of water=7-3.8=3.2 m/s
Radius of waterwheel =3 m
Rate of change of angular momentum=mvr/t=85×3×3.2=817 kgm2/s2
b)rate of change of angular momentum =torque=817Nm
c)power=817/5.5=148.54 j/s
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