#36 5.02 questions Precalculus

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cerpnyp18

Mathematics

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Explanation & Answer

L.H.S=sec^2(pi/2-x)-1

but we know sce(pi/2-x)=cosecx

then 

sec^2(pi/2-x)=cosec^2(x)

then

LHS=cosec^2(x)-1

but we know cosec^2(x)-1=cot^2(x)

then

LHS=cot^2(x)

so

L.H.S=R.H.S


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