Trigonometry Question

User Generated

zngufgvaxf101

Mathematics

Description

Given that sin A=-3/5 and the terminal side of angle A lies in the third quadrant and cos B=5/13 and the terminal side of angle B lies in the fourth quadrant, find:

a) Cos A

b) Sin 2A

c) sec^2 B

d) Cos(A-B)

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Explanation & Answer

Cos A =  -4/5

 Sin 2A = -6/5 * -4/5 = 24/25

 sec^2 B = 169/25

Cos (A-B) =  -4/13 + 36/65 = (-20+36)/65 = 16/65

Please let me know if you have any questions and best me if you are satisfactory.


Anonymous
I was struggling with this subject, and this helped me a ton!

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