Description
Me: You have a 15g piece of metal that is heated up at 180*c. You place this piece of metal in a calorimeter that holds 40g of water at 25*c. The calorimeter reads a temperature of 30*c as the highest temp. what is the specific heat of the metal?
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Explanation & Answer
DATA:
Mass of metal = 15g
∆T = 180C0 – 30C0 = 150C0
SOLUTION:
∆Q = mC∆T
For Q
Specific heat capacity of water = 4.186J/gC0
1g water = 4.186J
40g = (4.186*40)
= 167.44 J
∆Q = mC∆T
C = ∆Q/ m∆T
C = 167.44/(15*150)
C = 0.07441J/gC0
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