Description
Explanation & Answer
T(X)= (X-2)3 + 8
= (X3-6X2+12X -8) +8
T(X)=X(X2-6X +12)
Intercepts axes X:
X(X2-6X +12)=0
X= 0 is the only real solution (0,0)
Critic point:(turning point),(2,8)
T’(x)=3X2-12X+12=X2-4X+4=0 or ( x-2)2=0 , X=2 , T(2)=8
T increase from x=o , T(X) keeps increasing but faster than X<2