Description
A 4.0-g bullet leaves the muzzle of a rifle with a speed of 328 m/s. What force (assumed constant) is exerted on the bullet while it is traveling down the 0.80-m-long barrel of the rifle?
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Explanation & Answer
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The bullet starts from rest.original velocity = 0
final velocity = 328
displacement= .80
acceleration= ?
final velocity^2 = original velocity^2 + (2)(acceleration)(displacement)
107584= 1.6acceleration
acceleration = 67240
force = (mass)(acceleration)
The mass is 4g to make the units consistent we will convert to kg.
The mass is .004 kg
force = (.004)(67240) = 268.96 N
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Wind range: 50-65 mph daily
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-Depth of certain structures
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-You may want to look at the animal kingdom for some ideas
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