Four objects are held in position at the corners of a rectangle by light rods as

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a) here, moment of inertia = 

(2.9+2.1+4.3+2.5)*3^2 = 106.2 kgm^2 

because each mass is 3 m from the x axis 

b) now we consider distances from the y axis; each mass is 2m from the y axis: 

I=(2.9+2.1+4.3+2.5)*2^2=47.2 kgm^2 

c) the distance from the rotation axis is now found from the pythagorean theorem 

distance^2=2^2+3^2=13 

I=(2.9+2.1+4.3+2.5)*13=153.4 kgm^2

let me know if you have any questions thanks

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