whats the function off such that f'(x)=x^2 and f(-1)=0

User Generated

xfxhgivx

Mathematics

Description

how do I get the answer to the above question?

User generated content is uploaded by users for the purposes of learning and should be used following Studypool's honor code & terms of service.

Explanation & Answer

Thank you for the opportunity to help you with your question!

take integration of 

integrate[f'(x)]=integrate[x^2]

by integrating it we get
f(x) = (x^3)/3 + c
f(x) = (x^3)/3+ c
by putting 

f(-1)=0

we get
0 = [(-1)^3]/3 + c
c=1
so 
f(x)= (x^3)/3 + 1


let me know if you have any problem in understanding the answer
i will be happy to help
if you have more questions please put them on bids 
i will help you in less money with A+ work
best of luck :)

Please let me know if you need any clarification. I'm always happy to answer your questions.


Anonymous
This is great! Exactly what I wanted.

Studypool
4.7
Trustpilot
4.5
Sitejabber
4.4

Related Tags