Description
Explanation & Answer
Thank you for the opportunity to help you with your question!
r(t) = 1200 (1+ ((2t)/(1+t^2)) (0 ≤ t ≤ 5)
The increase in population after the 1st year is r(1).
r(1) = 1200 (1+ ((2*1)/(1+1^2)) = 1200(1+2/2) = 1200(1+1)
In the 2nd year, the increase is r(2),.
r(2) = 1200 (1+ ((2*2)/(1+2^2)) = 1200(1+4/5)
In the 3nd year, the increase is r(3),.
r(3) = 1200 (1+ ((2*3)/(1+3^2)) = 1200(1+6/10)
In the 4th year, the increase is r(4),
r(4) = 1200 (1+ ((2*4)/(1+4^2)) = 1200(1+8/17)
After 4 years the
population is 35,000 + r(1) + r(2) + r(3) + r(4) + r(5)
= 35000 + 1200[(1+1) + (1 + 4/5) + (1 + 6/10) + (1
+ 8/17) + (1+10/26)]
= 35000 + 1200*(6 +0.8+0.6+0.471+0.3846)
=35000+1200*8.2556
=35000+9906.73846
= 44906.738
= approx. 44907
Please let me know if you need any clarification. I'm always happy to answer your questions.
Review
Review
24/7 Homework Help
Stuck on a homework question? Our verified tutors can answer all questions, from basic math to advanced rocket science!