Description
The complete combustion of octane, C8H18, the main component of gasoline, proceeds as shown below.
2 C8H18(l) + 25 O2(g) → 16 CO2(g) + 18 H2O(l)
(a) How many moles of O2 are needed to burn 1.00 mol of C8H18?
(b) How many grams of O2 are needed to burn 1.75 g of C8H18?
(c) Octane has a density of 0.692 g/mL at 20°C. How many grams of O2 are required to burn 3.35 gal of C8H18?
Explanation & Answer
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a) 25 moles of O2 needed to burn 2 moles of C8H18. Hence 12.5 mole of O2 needed to burn 1 mole.
b)2.626g of O2
c)8.476g of O2