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The aquarium at Sea Critters Depot contains 140 fish. 80 of these fish are green swordtails 44 female and 36 male & 60 are orange swordtails 36 female & 24 males. A fish is randomly captured from the aquarium: (Round your answer to 4 decimal places.)
Probability the selected fish is a green swordtail? Pobability the selected fish is male? Probability the selected fish is a male green swordtail? Probability the selected fish is either a male or a green swordtail?
Explanation & Answer
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The desired outcome is green swordtail. There are 80 of those, in a total of 140. The probability is therefore 80/140 = 0.5714 or 57.14%
The desired outcome is a male fish. There are 36 male (from the green swordfish) plus 24 males (from the orange swordfish), so there is a total of 60 males, in a total of 140. The probability is therefore 60/140 = 0.4286 or 42.86%
The desired outcome is BOTH MALE AND GREEN, there are 36 male green fish, out of 140. Probability is 36/140 =0.2571 or 25.71%
The desired outcome is EITHER male OR green swordtail. There are 80 green fish, and there are 60 male in total. However, we are double counting, because we are considering "male green" in both of these numbers, so we actually only have 80+60-36= 104 male OR green fish, out of 140. So the probability is 104/140 = 0.7429
Please let me know if you need any clarification. Always glad to help!Review
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