Weighty Rope 15.20 Physics Using Calculus

timer Asked: Aug 28th, 2015

Question description

One end of a nylon rope is tied to a stationary support at the top of a vertical mine shaft of depth 76.0 m . The rope is stretched taut by a box of mineral samples with mass 25.0 kg attached at the lower end. The mass of the rope is 2.50 kg . The geologist at the bottom of the mine signals to his colleague at the top by jerking the rope sideways. (Do not neglect the weight of the rope.)

What is the wave speed at the bottom of the rope? 

I find 27.3 as the answer using the formula: v = sqrt(T/u) .... where T = force of tension and u = mass/unit length. So v = sqrt[(27.5*9.8)/(27.5/76)] = 

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