Description
a container ship made a trip to a navigational buoy and back. the trip there took four hours and the trip back took five hours. it averaged 5 km/h faster on the trip there than on the return trip. what was the container ships average speed on the out
Explanation & Answer
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let the speed of the return trip be x
So, the trip to there would have taken = x + 5 km/h
so, distance traveled while going = speed x time = (x + 5) * 4 = 4x + 20 km
and distance traveled while returning = speed x time = x*5 = 5x
Since the distance traveled while going and returning remains the same.
So,
4x + 20 = 5x
20 = 5x - 4x
x = 20
so, the average speed of trip there = x +5 = 20+ 5 = 25 km/h
and average speed of return trip = x = 20 km
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