# do a 12 question quiz for me (ALGEBRA 2) (LOG)

Anonymous
timer Asked: Aug 30th, 2015

Question description

i will provide my user info, and also inform you the LOG :

ometimes to simplify or evaluate logarithms you need to change the base.  This is very straight forward.

logab = (log b)/(log a)  = (ln b)/(ln a)

So log25 = log 5/log2  or = ln 5/ln2

Sometimes you will need to use change an exponential equation into the equivalent logarithmic equation and then use change of base to solve.

52x= 28

log5 28 = 2x

x = (1/2) log5 28 = (1/2) log 28/log 5

What do you do when you have two exponentials equal to one another with variables in both exponents?  Use the same approach

2x+2 = 3x

log2 3x = x+2

x log2 3 = x+2

x (log2 3 – 1) = 2

x = 2/( log2 3 – 1) = 2/[(log 3/log 2) – 1] = 3.419

On the quiz you will likely have a word problem.  If it asks about hydronium ion, it is represented as H3O+.

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