Algebra 2 math problem

User Generated

orgunal1973

Mathematics

Description

C-5d= -16

3c+2d= -14

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Explanation & Answer

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To solve this problem, you need to solve for one variable in one equation, then substitute that variable into the other equation:

1. Solve for c in the first equation:

c-5d=-16

c=5d-16

2. Plug c into the second equation, then solve for d:

3c+2d=-14

3(5d-16)+2d=-14

15d-48+2d=-14

17d=34

d=2

3.  Now plug d into either equation to solve for c:

c-5d=-16

c-5*2=-16

c-10=-16

c=-6




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Anonymous
Excellent resource! Really helped me get the gist of things.

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