Algebra 2 simplify completely. No negative exponents

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Oevgarlirtnf942

Mathematics

Description

1) (-3a^2bc)^3/18a^4b^5c^3

simplify completely. no negative exponents

2) Solve Absloute value 2m+3 minus 1 equals 11 

3) 3+7(2-5)^2+9-2^3

4) (a-y)^2+2y^3-3/a if a=-3 and y=2 

5) absolute value k equals 11

6) solve for m: Absloute value sign 2m +3 minus 1 equals 11

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Explanation & Answer

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1.= (-27a^6 b^3c^3)18a^4b^5c^3

=-1.5a^2b^-2

=-1.5a^2/b^2

2. alternative 1

2m+3-1=11

2m=11-2

m=4.5

alternative 2

-2m-3-1=11

-2m=11+4

m=-7.5


m=4.5 or m=-7.5

3. 3+7(2-5)^2+9-2^3

=3+7(9)+9-8

=3+63+1 =67

4. (a-y)^2+2y^3-3/a if a=-3 and y=2 

=(-1)^2 +8(8) +1

=1+64+1 =66

5 k=11 or k=-11

6. same as 2 above



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Anonymous
Just what I was looking for! Super helpful.

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