Description
1) (-3a^2bc)^3/18a^4b^5c^3
simplify completely. no negative exponents
2) Solve Absloute value 2m+3 minus 1 equals 11
3) 3+7(2-5)^2+9-2^3
4) (a-y)^2+2y^3-3/a if a=-3 and y=2
5) absolute value k equals 11
6) solve for m: Absloute value sign 2m +3 minus 1 equals 11
Explanation & Answer
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1.= (-27a^6 b^3c^3)18a^4b^5c^3
=-1.5a^2b^-2
=-1.5a^2/b^2
2. alternative 1
2m+3-1=11
2m=11-2
m=4.5
alternative 2
-2m-3-1=11
-2m=11+4
m=-7.5
m=4.5 or m=-7.5
3. 3+7(2-5)^2+9-2^3
=3+7(9)+9-8
=3+63+1 =67
4. (a-y)^2+2y^3-3/a if a=-3 and y=2
=(-1)^2 +8(8) +1
=1+64+1 =66
5 k=11 or k=-11
6. same as 2 above
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