Description
1) (-3a^2bc)^3/18a^4b^5c^3
simplify completely. no negative exponents
2) Solve Absloute value 2m+3 minus 1 equals 11
3) 3+7(2-5)^2+9-2^3
4) (a-y)^2+2y^3-3/a if a=-3 and y=2
5) absolute value k equals 11
6) solve for m: Absloute value sign 2m +3 minus 1 equals 11
Explanation & Answer
Thank you for the opportunity to help you with your question!
1.= (-27a^6 b^3c^3)18a^4b^5c^3
=-1.5a^2b^-2
=-1.5a^2/b^2
2. alternative 1
2m+3-1=11
2m=11-2
m=4.5
alternative 2
-2m-3-1=11
-2m=11+4
m=-7.5
m=4.5 or m=-7.5
3. 3+7(2-5)^2+9-2^3
=3+7(9)+9-8
=3+63+1 =67
4. (a-y)^2+2y^3-3/a if a=-3 and y=2
=(-1)^2 +8(8) +1
=1+64+1 =66
5 k=11 or k=-11
6. same as 2 above
Review
Review
24/7 Homework Help
Stuck on a homework question? Our verified tutors can answer all questions, from basic math to advanced rocket science!
Similar Content
Related Tags
The Outsiders
by S.E. Hinton
Crime and Punishment
by Fyodor Dostoyevsky
Siddhartha
by Hermann Hesse
Principles - Life and Work
by Ray Dalio
The Prince
by Niccolò Machiavelli
All the Kings Men
by Robert Penn Warren
Fools Crow
by James Welch
Too Much and Never Enough
by Mary L. Trump
Ezperanza Rising
by Pam Muñoz Ryan