Description
A pawnbroker buys a computer and a guitar for $500. He sells the computer at a markup of 40%, but has to take a loss of %10 on the guitar in order to sell it. if he makes a profit of $110 on the sale of the two items, what did he pay for the computer?
Explanation & Answer
Thank you for the opportunity to help you with your question!
Let the buying price of computer be X and buying price of guitar be Y.
x+y= 500
x= 500-y
40% x -10%y =110
0.4(500-y ) -0.1y =110
200 -0.4y-0.1y =110
-0.4y-0.1y =110-200
-0.5y =-90
y=-90/-0.5
y= 180
x= 500-180 = 320
the buying price of the computer is thus $320
Please let me know if you need any clarification. I'm always happy to answer your questions.Review
Review
24/7 Homework Help
Stuck on a homework question? Our verified tutors can answer all questions, from basic math to advanced rocket science!
Similar Content
Related Tags
The Aftermath
by Rhidian Brook
The 48 Laws of Power
by Robert Greene
American Gods
by Neil Gaiman
The Book Thief
by Markus Zusak
Killers of the Flower Moon
by David Grann
Good Kids Bad City
by Kyle Swenson
The Scarlet Letter
by Nathaniel Hawthorne
Calypso
by David Sedaris
Othello
by Wiliam Shakespeare