Please help me solve this!!!

User Generated

EurggO

Mathematics

Description

A pawnbroker buys a computer and a guitar for $500. He sells the computer at a markup of 40%, but has to take a loss of %10 on the guitar in order to sell it. if he makes a profit of $110 on the sale of the two items, what did he pay for the computer?

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Explanation & Answer

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Let the buying price of computer be X and buying price of guitar be Y.

x+y= 500

x= 500-y

40% x -10%y =110

0.4(500-y ) -0.1y =110

200 -0.4y-0.1y =110

-0.4y-0.1y =110-200

-0.5y =-90

y=-90/-0.5

y= 180

x= 500-180 = 320

the buying price of the computer is thus $320

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