# CHEMISTRY - Help calculating grams of excess reactant

Anonymous

Question description

Ammonia rapidly reacts with hydrogen chloride, making ammonium chloride. Write a balanced chemical equation for the reaction, and calculate the # of grams of excess reactants when 3.0 g of NH3 reacts with 5.0 g of HCL.

So, I believe the eq. is already balanced: NH3 + HCl > NH4Cl

What I have so far is this:

Molar Masses:

NH3 = 17 g/mol, HCl = 36 g/mol, NH4Cl = 53 g/mol

# Moles:

NH3 = 0.1765 moles (excess reactant)

HCl = 0.1389 moles (limiting reactant)

First, how am I finding the mole ratio? Is it not just 1:1:1 (1 mole NH3 reacts with 1 mole of HCl to form 1 mole NH4Cl)?

I'm also confused on how to find the number of grams of the excess, because wouldn't it just be 3 grams? I used the # of grams to find the number of moles, so to "calculate" the # of grams I'm just undoing what I've just done, right?

I'm not really sure where to go from here.

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