Description
1. Rob throws a baseball upwards at 14.2 m/s. His friend, John, is sitting in a tree 4.5m above Rob.
a. Calculate how long it will take to reach John.
b. If John misses the ball as it moves upwards, how long will it take to reach John again.
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Explanation & Answer
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vf^2 = vi^2 -2 • a • d
0^2=14.2^2- 2 x a x 4.5
0 = 201.64-9a
9a=201.64
a= 22.4
v=v-at
0= 14.2 - 22.4t
22.4t=14.2
t=0.63 sec
for return
o.63x2=1.26sec
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