Beginning Algebra-Applications

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QnaalI49

Mathematics

Description

The length of a rectangular piece of steel in a bridge is 3 meters less than double the width. The perimeter of the piece of steel is 42 meters. Find the length of the piece of steel. Find the width of the piece of steel.

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Explanation & Answer

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Let the length = L

Let the width = W

Now

length of a rectangular piece of steel in a bridge is 3 meters less than double the width

Meaning

L=2W-3

Perimeter = 2(Length + width)

                 =2(2W-3+W)

                24  =2(3W-3)

             or

             6W-6=24

              6W=30

              W=30

Width is 30 meters

Length = 2*30-3 = 60-3 = 57 meters.

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