Description
For a certain urban area, in a random sample of 5 months, an average of 28 mail carriers were bitten by dogs each month. The standard deviation of the sample was 3. Find the 90% confidence interval of the true mean number of mail carriers who are bitten by dogs each month. Assume the variable is nor distributed.
Explanation & Answer
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At 90 percent level of confidence from the tables we get 2.132
Then we calculate the true mean
28+or- 2.132(3/square root5)
this gives us 25.15<u<30.85 as our true mean
Please let me know if you need any clarification. I'm always happy to answer your questions.Review
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