# R(f)= (30 5f)(200-20f)

FratBro23
Category:
Mathematics
Price: \$5 USD

Question description

A gym has 200 member who pay \$30 per month for unlimited use of the gym's equipment.  A survey of the member indicates that for each \$5 increase in the monthly fee.  The gym will lose 20 members.  This mens that the revenue R from fee, which is currently \$6000 per month, will become R(f)= (30+5f)(200-20f)=-100f^ + 400f +6000 where f is a whole number of \$5 fee increases.  For what number of \$5 fee increases.  For what number of \$5 fee increase will the revenue from fees actually be less than its current value?

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