Description
A 32.5 g Iron rod, initially at 22.7 degree C, is submerged into an unknown mass of water at 63.2 degree C, in an insulated container. The final temperature of the mixture upon reaching thermal equilibrium is 59.5 degree C. What is the mass of the water?
Explanation & Answer
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We have to find the unknown mass of water.
Given,
mass of iron=32.5 g
Specific heat of iron=.45J/g degree C
Change in temperature=>59.5-22.7=36.8 degree Celsius
mass of water=to calculate(Suppose it is m gram)
Specific heat of water=4.184 J/g degree C
Change in temperature=63.2-59.5 =3.7
Now heat gained by iron=mCdT
m=mass of iron,C=specific heat of iron=.45J/g degree C,dT=36.8
Now heat gained by iron is equal to heat lost by water.Please rate my answer so that I can help you further in the future.
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