CSCC Statistics Test Final
stats test
4
.The National Institute of Health randomly selected 520individuals who gave blood during the month of May in order todetermine their blood types. The NIH plotted the percentage of theblood types in the pie chart depicted below.
What
is the number
of individuals from this sample who have blood type B?
16
20
28
36
104
5.
Regarding the pie chart image presented below (as well as in the
question above), what component of a good statistical picture is
missing?
Title
Labeling
The
Source
A
Line graph
6 Which
of the following might you use to best
display categorical
data?
Histogram
Pictogram
Line
graph
Stem
plot
Scatter
plot7.
You
have collected data on nurses’ annual salaries over a ten-year
period (2009 to 2019). Which of the following data organization
schemes would best highlight upward and downward changes over time?
Pictogram
Line
graph
Bar
graph
Pie
chart
Scatterplot
8.
Ohio
University sorted 150 new students into one of the four residence
hall greens as follows: East Green 44, South Green 40, West Green 35,
and North Green 31. In a Chi-Square test, what would EXPECTED
value (i.e., Expected Frequency)
be for the East Green?
37.5
42
44
84
1509.
A
Chi-square goodness-of-fit test was conducted on voter preferences in
a state primary (with candidates A, B, C, and D) that yielded a
calculated/obtained statistic of 7.82. If you used a critical value
of 6.22 to determine if the voters significantly preferred one
candidate over another, what conclusion would you draw?
Voters
showed no significant preference
Voters
showed a significant preference
Voters
showed a significant preference for candidate A over the others
Not
enough information is given to be able to answer this question
Answers
B and C are both correct10.Calculate
the expected value (i.e.,
expected frequency) for each
cell of the table below, for this Chi-Square Test for Independence.
What is the expected
value/frequency for the
Senior/Yes cell?
22.5
27.5
50
67.5
10011.
Ohio
University sorted 150 new students into one of the four residence
hall greens as follows: East Green 44, South Green 40, West Green 35,
and North Green 31. Which is the appropriate test to use to
determine whether there was a preference
regarding the green to which students were assigned?
Goodness
of Fit test
Test
for Independence
Parametric
test of significance
Z-test
T-test
12.
Which
of the following statistical tests would be appropriate to perform on
the data in the table depicted here?
Goodness
of Fit test
Test
for Independence
Parametric
test of significance
Z-test
T-test
13.
A
potential sponsor would like to know whether local viewers prefer
some evening news programs over others. The sponsor conducts a viewer
preference
survey based on a simple random sample of 260 households. The results
are: 54 preferred KTVO, 49 preferred KMDT, 68 preferred KLPF, and 89
preferred KZTV. A goodness-of-fit test performed on these data would
yield a calculated/obtained chi-square value of ______:
44.0
/ 40.0
2.72
7.90
60.0
/ 56.0
14.8014.
You
flip a coin four times. What is the probability of getting the
specific
outcome
of all heads on each of the four times instead of tails on each
of the four times?
0.00
0.50
0.25
1.00
none
of the above
15.
Event A has a probability of 0.25 and Event B has a probability
of 0.00. What is the probability associated with the joint occurrence
of these two independent
events?
0.00
0.50
0.25
1.00
none
of the above
16.
Bob has 15 colors of paints. He mixes 2 colors at a time. How many
different colors does he get when he mixes all possible pairs of
paints? This problem is an example of a _______________:
joint
probability
conditional
probability
combination
permutation
"given
that" probability17.
Let
us assume that all 102 students in this course are in one and only
one of the following programs: the TAS program, the BA program, or
the RN to BSN program. Let us assume further that the number of
students in each of these programs is equivalent (in other
words, there are 34 students in each program). What
is the probability of a student in this course being in either
the TAS program or
the BA program?
0.1111
0.3333
0.6667
0.9999
cannot
be determined
18.
A student who is
graduating from a large college is randomly selected. Which of the
following is the correct wording and interpretation of this
probability statement?
p(J
/ N), where J represents the student getting a job, and N
represents the student networking with local employers
The
probability that a randomly selected student gets a job
The
probability that a randomly selected student gets a job and
networks with local employers
The
probability that a randomly selected student networks with local
employers given that the student gets a job
The
probability that a randomly selected student gets a job given that
the student networks with local employers
The
probability that a randomly selected student gets a job or
networks with local employers
19.
Ten students from
this class are running a race. How many different ways
are there for the 10 students to get first, second, and third
place? This question is an example of a _____________:
joint
probability
conditional
probability
combination
permutation
either/or
probability
20.
Five students from
this class are running a race. How many different ways are
there for the 5 students to get first, second, and third
place? For
this problem, what is N?
3
4
5
6
none
of the above21.
Five
students from this class are running a race. How many different
ways are there for the 5 students to get first, second, and
third place? For
this problem, what is r?
3
4
5
6
none
of the above22.
Five
students from this class are running a race. How many different
ways are there for the 5 students to get first, second, and
third place? What is the calculated value for this problem?
3
10
15
20
60
23.
To
drum up business and to get customers to try different varieties
of cupcakes, a local bakery is offering one free “luck of the draw”
cupcake. That is, a cupcake is randomly selected from what is on hand
and given to the customer to try. Currently, the cupcakes available
are made of chocolate, vanilla, or strawberry and have one of three
toppings: rainbow sprinkles, chocolate chips, or gummy bears. The
different configurations of the 100 cupcakes available for the “luck
of the draw” promotion are depicted in the table below.
What
is the probability of receiving a chocolate cupcake with rainbow
sprinkles?
0.1395
0.3000
0.0600
0.1000
0.0500
24.
To
drum up business and to get customers to try different varieties
of cupcakes, a local bakery is offering one free “luck of
the draw” cupcake. That is, a cupcake is randomly
selected from what is on hand and given to the customer to
try. Currently, the cupcakes available are made of
chocolate, vanilla, or
strawberry and have one of three toppings: rainbow
sprinkles, chocolate chips, or gummy bears. The
different configurations of the 100 cupcakes available for
the “luck of the draw” promotion are depicted in the
table below.What
is the probability that a cupcake is strawberry given
that
it has rainbow sprinkles?
0.3636
0.3429
0.1200
0.3300
none
of the above
25.
To
drum up business and to get customers to try different varieties
of cupcakes, a local bakery is offering one free “luck of
the draw” cupcake. That is, a cupcake is randomly
selected from what is on hand and given to the customer to
try. Currently, the cupcakes available are made of
chocolate, vanilla, or
strawberry and have one of three toppings: rainbow
sprinkles, chocolate chips, or gummy bears. The
different configurations of the 100 cupcakes available for
the “luck of the draw” promotion are depicted in the
table below.
What
is the probability that a cupcake is vanilla with either
rainbow sprinkles or
gummy bears?
0.1395
0.2666
0.0880
0.1444
0.130026.
(9!)
/ (5!) =
3,024
5040
43,545,600
604800
In
statistics, we cannot divide or multiply factorials27. During
which decade
was inflation the highest, as measured by the percentage change in
the CPI?
1940s
1950s
1960s
1970s
1980s28.
What
was the rate of inflation during the decade
of the 1950s, as measured by percentage change in CPI?
22.82%
31.08%
58.62%
72.14%
112.37%
29.
The average price of a new house was $3,395 in 1915, when the
CPI was 10.1. How much would the average new house cost in 1995 when
adjusted for inflation? (The CPI in 1995 was 152.4.)
$34,289.50
$43,580.20
$51,227.52
$73,892.54
$87,652.8930.
What
was the rate of inflation during the decade
of the 1980s, as measured by percentage change in CPI?
22.82%
31.08%
58.62%
72.14%
112.37%31.
Using
1989 as a base, the price index for computers is now 185. What does
this index number mean?
The
price of computers has decreased 85% since 1989
The
price of computers has increased 85% since 1989
The
price of computers has increased 185% since 1989
The
price of computers has increased 100% since 1989
The
price of computers is now $185 more than in 198932.
An economic
indicator that is _____________ is one in which the highs, lows, and
changes tend to come after or following changes in the economy.
leading
receding
preceding
sluggish
lagging33. Which
one of the following is NOT
one of the major uses of the CPI?
The
CPI is used to evaluate and determine economic policy.
The
CPI is used to determine economic trends in the rural United
States.
The
CPI is used to compare prices in different years.
The
CPI is used to determine salary and price adjustments.
All
of the above answers are major uses of the CPI.34.
Much
of the rest of the exam is based on the following problem:In
the general population, patients who are recovering from bronchial
pneumonia normally take a mean (average) of 4.75 days to leave
the hospital, with a population
standard deviation
of 1.82 days. Medical personnel at a hospital are trying a
new medication that is designed to ease breathing during
recovery. What is not currently known is whether the new medication
will impact duration of hospital stay. The first sample of 25
patients (n=25) to whom this medication was administered
were released from the hospital in a mean (average) of 2.60
days. Based on this result, should the hospital conclude that there
is a significant
difference
in duration of hospital stay because of the new medication?
The
appropriate statistical procedure for this problem would be a
___________?
t-test
z-test
Chi-square
Goodness of Fit
Chi-square
Test for Independence
Pearson
r correlation35.
In
the general population, patients who are recovering from bronchial
pneumonia normally take a mean (average) of 4.75 days to leave
the hospital, with a population
standard deviation of
1.82 days. Medical personnel at a hospital are trying a
new medication that is designed to ease breathing during
recovery. What is not currently known is whether the new medication
will impact duration of hospital stay. The first sample of 25
patients (n=25) to whom this medication was administered
were released from the hospital in a mean (average) of 2.60
days. Based on this result, should the hospital conclude that there
is a significant
difference in
duration of hospital stay because of the new medication?
What
type of test is this?
One-tailed
Two-tailed
Three-tailed
Four-tailed
Joint
conditional probability36.
In
the general population, patients who are recovering from bronchial
pneumonia normally take a mean (average) of 4.75 days to leave
the hospital, with a population
standard deviation of
1.82 days. Medical personnel at a hospital are trying a
new medication that is designed to ease breathing during
recovery. What is not currently known is whether the new
medication will impact duration of hospital stay. The first
sample of 25 patients (n=25) to whom this medication was
administered were released from the hospital in a mean
(average) of 2.60 days. Based on this result, should the hospital
conclude that there is a significant
difference in
duration of hospital stay because of the new medication? The
most appropriate alternative hypothesis (in symbols) would be:
newmed =
4.75
newmed =
2.60
newmed
≠
4.75
newmed <
4.75
newmed >
2.60
37.
In
the general population, patients who are recovering from bronchial
pneumonia normally take a mean (average) of 4.75 days to leave
the hospital, with a population
standard deviation of
1.82 days. Medical personnel at a hospital are trying a
new medication that is designed to ease breathing during
recovery. What is not currently known is whether the new
medication will impact duration of hospital stay. The first
sample of 25 patients (n=25) to whom this medication was
administered were released from the hospital in a mean
(average) of 2.60 days. Based on this result, should the hospital
conclude that there is a significant
difference in
duration of hospital stay because of the new medication?
The
most appropriate null hypothesis (in symbols) would be:
newmed =
2.60
newmed
= 4.75
newmed >
2.60
newmed > 4.75
newmed <
2.6038.
n
the general population, patients who are recovering from bronchial
pneumonia normally take a mean (average) of 4.75 days to leave
the hospital, with a population
standard deviation of
1.82 days. Medical personnel at a hospital are trying a
new medication that is designed to ease breathing during
recovery. What is not currently known is whether the new
medication will impact duration of hospital stay. The first
sample of 25 patients (n=25) to whom this medication was
administered were released from the hospital in a mean
(average) of 2.60 days. Based on this result, should the hospital
conclude that there is a significant
difference in
duration of hospital stay because of the new medication?For
this problem, the correct sign for the critical value should be:
+
-
<
>
+/-39.
In
the general population, patients who are recovering from bronchial
pneumonia normally take a mean (average) of 4.75 days to leave
the hospital, with a population
standard deviation of
1.82 days. Medical personnel at a hospital are trying a
new medication that is designed to ease breathing during
recovery. What is not currently known is whether the new
medication will impact duration of hospital stay. The first
sample of 25 patients (n=25) to whom this medication was
administered were released from the hospital in a mean
(average) of 2.60 days. Based on this result, should the hospital
conclude that there is a significant
difference in
duration of hospital stay because of the new medication? Which
of the following is the critical value associated with an alpha
level of .05 that you should use to evaluate the null hypothesis?
(Use your tables.)
1.65
1.70
1.96
2.58
2.6040.
In
the general population, patients who are recovering from bronchial
pneumonia normally take a mean (average) of 4.75 days to leave
the hospital, with a population
standard deviation of
1.82 days. Medical personnel at a hospital are trying a
new medication that is designed to ease breathing during
recovery. What is not currently known is whether the new
medication will impact duration of hospital stay. The first
sample of 25 patients (n=25) to whom this medication was
administered were released from the hospital in a mean
(average) of 2.60 days. Based on this result, should the hospital
conclude that there is a significant
difference in
duration of hospital stay because of the new medication? The
most appropriate null hypothesis (in words) should be:
There
is a significant difference in the duration of hospital stay
when patients administered the new medication are compared to
the general population of patients not receiving this
medication.
There
is no significant difference in the duration of hospital stay
when patients administered the new medication are compared to
the general population of patients not receiving this
medication.
Duration
of hospital stay is not significantly increased for patients
administered the new medication compared to the general
population of patients not receiving this medication.
Duration
of hospital stay is significantly decreased for patients
administered the new medication compared to the general
population of patients not receiving this medication41.
In
the general population, patients who are recovering from bronchial
pneumonia normally take a mean (average) of 4.75 days to leave
the hospital, with a population
standard deviation of
1.82 days. Medical personnel at a hospital are trying a
new medication that is designed to ease breathing during
recovery. What is not currently known is whether the new
medication will impact duration of hospital stay. The first
sample of 25 patients (n=25) to whom this medication was
administered were released from the hospital in a mean
(average) of 2.60 days. Based on this result, should the hospital
conclude that there is a significant
difference in
duration of hospital stay because of the new medication? The
most appropriate alternative hypothesis (in words) would be:
There
is no significant difference in the duration of hospital stay
when patients administered the new medication are compared to
the general population of patients not receiving this
medication.
There
is a significant difference in the duration of hospital stay
when patients administered the new medication are compared to
the general population of patients not receiving this
medication.
Duration
of hospital stay is significantly decreased for patients
administered the new medication compared to the general
population of patients not receiving this medication.
Duration
of hospital stay is significantly increased for patients
administered the new medication compared to the general
population of patients not receiving this medication.
42.
In
the general population, patients who are recovering from bronchial
pneumonia normally take a mean (average) of 4.75 days to leave
the hospital, with a population
standard deviation of
1.82 days. Medical personnel at a hospital are trying a
new medication that is designed to ease breathing during
recovery. What is not currently known is whether the new
medication will impact duration of hospital stay. The first
sample of 25 patients (n=25) to whom this medication was
administered were released from the hospital in a mean
(average) of 2.60 days. Based on this result, should the hospital
conclude that there is a significant
difference in
duration of hospital stay because of the new medication? What
is the value of the standard error?
0.36
0.54
1.19
2.10
4.6043.
In
the general population, patients who are recovering from bronchial
pneumonia normally take a mean (average) of 4.75 days to leave
the hospital, with a population
standard deviation of
1.82 days. Medical personnel at a hospital are trying a
new medication that is designed to ease breathing during
recovery. What is not currently known is whether the new
medication will impact duration of hospital stay. The first
sample of 25 patients (n=25) to whom this medication was
administered were released from the hospital in a mean
(average) of 2.60 days. Based on this result, should the hospital
conclude that there is a significant
difference in
duration of hospital stay because of the new medication? Which
of the following is the calculated/obtained test statistic for
this problem?
t
= 1.96
z
= 1.96
t
= 5.91
z
= 5.91
z
= 2.7144.
In
the general population, patients who are recovering from bronchial
pneumonia normally take a mean (average) of 4.75 days to leave
the hospital, with a population
standard deviation of
1.82 days. Medical personnel at a hospital are trying a
new medication that is designed to ease breathing during
recovery. What is not currently known is whether the new
medication will impact duration of hospital stay. The first
sample of 25 patients (n=25) to whom this medication was
administered were released from the hospital in a mean
(average) of 2.60 days. Based on this result, should the hospital
conclude that there is a significant
difference in
duration of hospital stay because of the new medication? Based
on your results, which decision would you make?
reject
the null hypothesis
fail
to reject the null hypothesis
reject
the alternator hypothesis
fail
to reject the alternator hypothesis
retain
the alternator hypothesis45.
In
the general population, patients who are recovering from bronchial
pneumonia normally take a mean (average) of 4.75 days to leave
the hospital, with a population
standard deviation of
1.82 days. Medical personnel at a hospital are trying a
new medication that is designed to ease breathing during
recovery. What is not currently known is whether the new
medication will impact duration of hospital stay. The first
sample of 25 patients (n=25) to whom this medication was
administered were released from the hospital in a mean
(average) of 2.60 days. Based on this result, should the hospital
conclude that there is a significant
difference in
duration of hospital stay because of the new medication? The
best conclusion for this problem is:
There
is a significant difference in the duration of hospital stay
when patients administered the new medication are compared to
the general population of patients not receiving this
medication.
There
is no significant difference in the duration of hospital stay
when patients administered the new medication are compared to
the general population of patients not receiving this
medication.
Duration
of hospital stay is significantly decreased for patients
administered the new medication compared to the general
population of patients not receiving this medication.
Duration
of hospital stay is significantly increased for patients
administered the new medication compared to the general
population of patients not receiving this medication.
46.
In
the general population, patients who are recovering from bronchial
pneumonia normally take a mean (average) of 4.75 days to leave
the hospital, with a population
standard deviation of
1.82 days. Medical personnel at a hospital are trying a
new medication that is designed to ease breathing during
recovery. What is not currently known is whether the new medication
will impact duration of hospital stay. The first sample of 25
patients (n=25) to whom this medication was administered
were released from the hospital in a mean (average) of 2.60
days. Based on this result, should the hospital conclude that there
is a significant
difference in
duration of hospital stay because of the new medication? If
you were to calculate the 99% confidence interval, the mean that you
would use in this calculation is ____:
4.60
3.20
4.75
2.60
1.8247. Whenever
we reject the null hypothesis, as researchers what type of error
are we most concerned that we may have made?
Standard
error
Null
hypothesis error
Alternative
hypothesis error
Type
II statistical error
Type
I statistical error
48.
In
the general population, patients who are recovering from bronchial
pneumonia normally take a mean (average) of 4.75 days to leave
the hospital, with a population
standard deviation of
1.82 days. Medical personnel at a hospital are trying a
new medication that is designed to ease breathing during
recovery. What is not currently known is whether the new medication
will impact duration of hospital stay. The first sample of 25
patients (n=25) to whom this medication was administered
were released from the hospital in a mean (average) of 2.60
days. Based on this result, should the hospital conclude that there
is a significant
difference in
duration of hospital stay because of the new medication? If
you were to calculate the 99% confidence interval, what is the
critical value that you would use?
+/-
1.65
+/-
1.70
+/-
1.96
+/-
2.33
+/-
2.58
49.
In
the general population, patients who are recovering from bronchial
pneumonia normally take a mean (average) of 4.75 days to leave
the hospital, with a population
standard deviation of
1.82 days. Medical personnel at a hospital are trying a
new medication that is designed to ease breathing during
recovery. What is not currently known is whether the new medication
will impact duration of hospital stay. The first sample of 25
patients (n=25) to whom this medication was administered
were released from the hospital in a mean (average) of 2.60
days. Based on this result, should the hospital conclude that there
is a significant
difference in
duration of hospital stay because of the new medication? Calculate
the 99% confidence interval. Which 2 values will be
required to complete the equation for the confidence interval?
2.1416
< µ < 4.2584
1.7319
< µ < 3.4281
1.6609
< µ < 3.5391
1.8068
< µ < 4.5932
0
< µ < 1.96
50.
If α = .05
and β = .25, calculate the following: The
statistical decision is to reject the null, and H0
(the null) is really false (i.e., Power)
.05
.25
.75
.95
.01
51.
If α = .05
and β = .25, calculate the following: The
statistical decision is to fail reject the null, and H0
(the null) is really true (i.e., a correct decision)
.05
.75
.20
.01
.9552.
If α
= .05 and β = .25, calculate the following: The
statistical decision is to reject the null, and H0
(the null) is really true (i.e., a Type I error)
.05
.99
.20
.95
.01
53.
If α = .05
and β = .25, calculate the following: The
statistical decision is to fail to reject the null, and H0
(the null) is really false (i.e., a Type II error)
.05
.25
.75
.95
.01