Need algebra help with the terms in the 1st sum that are consecutive terms of an arithmetic sequence

timer Asked: Nov 30th, 2015
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School: UIUC

Thank you for the opportunity to help you with your question!

a. sum s=n/2*(2a+(n-1)*d), here a=6, d=3. now, 444=a+(n-1)*d, so n=(444-6)/3+1=147. 

hence sum, s=147/2*(12+(147-1)*3)=33075

b. sum s=4*127*(127+1)/2-11*127=31115

Please let me know if you need any clarification. I'm always happy to answer your questions.

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