# I'm learning how to solve poly

**Question description**

I'm learning how to solve polynomials by using the quadratic equation. But I'm just not getting it. I learn best by watching how the problem is solved. Can anyone help me with steps on the following? Thank you so much!3x(3x-1)=1This is what I have so far:3x(3x-1)=1.... 3x(3x-1)-1=0.... 9x^2-3x-1=0x=(3+/- (√-3^2-4(9)(-1)) ) / 2(9).... x=(3+/- √27 ) / 18So, I understand how to put the terms into quadratic equation form and simplify them. I'm just getting lost toward the end. Any help would be appreciated!

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