Intergration help, area under a graph

Anonymous
timer Asked: Feb 25th, 2016

Question description

The electric current (i) in a device varies with time (t). The equation linking the two variables is 

i=2sin(5t)

The area under the graph represents the charge (Cuolombs) that has passed over any given time interval.

Calculate the area and hence charge by intergrating the equation between t=t1 and t=t2

t1= 0.4 and t2=0.5

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