incompleted code

Anonymous
timer Asked: Mar 14th, 2016

Question description

#include <string>

#include <iostream>

using namespace std;

#define n 10

int m[n][n], X, Y;

void generMat(){ for (int x = 0; x < n; x++) for (int y = 0; y < n; y++) m[x][y] = rand() % 100; } //create data in array y[]

void printMat(){ for (int x = 0; x < n; x++) { for (int y = 0; y < n; y++) cout << m[x][y] << '\t'; cout << endl; } cout << endl;}

void swap(int &a, int &b){ int t = a; a = b; b = t; }

//The next two functions must be completely written by the students

void minInRow() { int minInRowX = 999, t=0; for (int c = 0; c < n; c++) if (m[X][c] < minInRowX){ t = c; minInRowX = m[X][c]; } swap(m[X][Y], m[X][t]); } //to complete by students

void maxInCol() { int minInColY = 0, t = 0; for (int r = 0; r < n; r++) if (m[r][Y] > minInColY){ t = r; minInColY = m[r][Y]; } swap(m[X][Y], m[t][Y]); } //to complete by students

//MidExam: n Cities located at <X,Y> coordinates, provided by this function:

int City[n][2]; //city <x,y> Coords

float Dist[n][n]; //adjacency matrix to show distances between <From, To> city_pair

void createMapCoords()

{

for (int Ci = 0; Ci < n; Ci++) for (int Co = 0; Co < 2; Co++) City[Ci][Co] = rand() % 100;

cout << "\nCity <x y> coords\n";

for (int x = 0; x < n; x++) { cout << x << ") "; for (int y = 0; y < 2; y++) cout << City[x][y] << '\t'; cout << endl; } cout << endl;

}

void plotMap() //draw the map with points representing the city locations

{

cout << "\nM A P \n\n";

string map[n][n];

for (int i = 0; i < n; i++)for (int j = 0; j < n; j++) map[i][j] = " "; //init map

for (int i = 0; i < n; i++) map[int(.1*City[i][0])][int(.1*City[i][1])] = ". "; //place the n cities on the map

for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) cout << map[i][j]; cout << endl; }

cout << endl;

}

void answer() //print the distances in this (adjacency matrix)

{

plotMap();

for (int i = 0; i < n; i++) for (int j = 0; j < n; j++) Dist[i][j] = 0.; //initialize Dist[n][n] to zeros

/*write your code here to calculate distances, and find the smallest distance, and print the found closest pair of cities

Remember how to calculate the distance between two cities:

if X1,Y1, and X2, Y2 are the coords of X, and Y cities: then Dist = sqrt((X2-X1)*(X2-X1) + (Y2-Y1)*(Y2-Y1))

*/

cout << "\n<from,to> City Distances \tADJACENCY MATRIX\n\n";

cout <<" To>>\t"; for (int j = 0; j < n; j++) cout << j << '\t'; cout << endl;

cout << "\nFrom\n----\n";

for (int i = 0; i < n; i++) { cout <<'\n' <<i << ")\t"; for (int j = 0; j < n; j++) cout << Dist[i][j] << '\t'; cout << endl; } cout << endl;

}

void main()

{ //1- Last Program Correction may help you to complete the mid term exam:

generMat(); printMat();

cout << "Enter a position: "; cin >> X >> Y;

minInRow(); printMat(); //m[X][Y] becomes minInRow X

maxInCol(); printMat(); //m[X][Y] becomes maxInCol Y

//2- MidExam: (To complete by students in class)

//Given <n> Cities located at <X,Y> coordinates, provided by this function:

createMapCoords(); //this is a complete working code.

//Find the closest two cities, and calculate the complexity big_O() of your algorithm: answer()

answer(); // complete working code is given to you here, but

// You have to complete the distance calculation, and print the smallest one

system("pause");

}


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