# J The average kinetic energy o

Anonymous

Question description

J The average kinetic energy of an electron in a ground-state helium atom is 2.4 x 103 kJ/mol. A. What is the corresponding electron velocity using KE = ½ mv2 ? Remember to convert energy/mol of electrons into KE/one electron first! B. An experiment is able to measure this velocity with an uncertainty of 10%. Calculate the minimum uncertainty in the position (∆x) of the electron for this experiment. Hints: First find 10% of the velocity you calculated above (∆v). Then solve ∆x∆v ≥ h/4πm for ∆x. To obtain a minimum, use an = instead of a ≥. C. The effective radius of a helium atom is 130 pm. Is the uncertainty in the position you calculated above a significant fraction of this effective radius? Include a sketch and a calculation in your answer.

(Top Tutor) Studypool Tutor
School: UCLA
Studypool has helped 1,244,100 students
flag Report DMCA

Brown University

1271 Tutors

California Institute of Technology

2131 Tutors

Carnegie Mellon University

982 Tutors

Columbia University

1256 Tutors

Dartmouth University

2113 Tutors

Emory University

2279 Tutors

Harvard University

599 Tutors

Massachusetts Institute of Technology

2319 Tutors

New York University

1645 Tutors

Notre Dam University

1911 Tutors

Oklahoma University

2122 Tutors

Pennsylvania State University

932 Tutors

Princeton University

1211 Tutors

Stanford University

983 Tutors

University of California

1282 Tutors

Oxford University

123 Tutors

Yale University

2325 Tutors