polynomial functions multiple choice
Question Description
Estimate the zeros of the function shown in the graph below.
{-2.9, -1, 0.8}
{-2, 0}
{-2, -1, 0}
{-2.9, -1, -2, 0.8
=========================
In the function shown in the chart below, at which values of x are there relative minima or maxima?
x | f(x) |
-3 | -2 |
-2 | 2 |
-1 | 0 |
0 | -2 |
1 | 2 |
2 | 18 |
3 | 52 |
2 and -2
-3 and 3
-2 and 0
-3, 0, and 3
============================
In the function shown in the chart below, between what values of x would you find the zeros of the function?
x | f(x) |
-3 | 73 |
-2 | 8 |
-1 | -7 |
0 | -8 |
1 | -7 |
2 | 8 |
3 | 73 |
-1 and 0, 0 and 1
-2 and -1, 1 and 2
-7 and 8, -8 and -7
1 and -1
============================
Which of the following could be the graph of f(x) = x3 + x2 - 3x?
A. | B. |
C. | D. ======== |
========================================
Estimate the relative maximums in the graph below.
(1.3, 1.4) and (-0.6, 2.6)
(-0.6, 2.6,), (0.5, 0.3), and (1.3, 1.4)
(-1, 0) and (1.8, 0)
(-1, 0), (0, 1), and (1.8, 0)
====================
Which of the following shows a graph that meets the following conditions.
I. As x → ∞, f(x) → ∞
II. The degree of f(x) is odd
III. the leading coefficient is positive
A. | B. |
C. | D. |
=====================================
For the graph below, which of the following is true?
I. As x → ∞, f(x) → ∞
II. As x → ∞, f(x) → -∞
III. As x → -∞, f(x) → ∞
IV. As x → -∞, f(x) → -∞
V. f(x) is odd
VI. the leading coefficient is negative
I, III, and V are true
II, III, V, and VI are true
II, III, and V are true
II, IV, V, and VI are true
====================================
Find r(x + 1) if r(x) = x3 + x + 1
x3 + 3x2 + 4x + 3
x3 + 4x2 + 5x + 3
x3 + 2x + 3
x4 + x3 + x2 + 2x + 1
=======================
Find p(-4) if p(x) = x5 - x2
1040
-1040
1008
-1008
============================
What is the degree and leading coefficient of the polynomial below?
6x3 + 3x4 = 2x2 - 2
degree = 4, leading coefficient = 3
degree = 3, leading coefficient = 6
degree = 2, leading coefficient = 2
degree = 0, leading coefficient = -2
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