To participate, choose ONE of the problems listed in the Discussion Problems Column that has not alr

User Generated

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Mathematics

Description

For this week, consider these exercises:

Section Number

Discussion Problems

6.1

16, 18, 24, 30, 32

6.2

2 – 26 (even)

6.3

18, 24, 26, 28, 32, 34

6.4

4, 8, 12, 16, 20, 24, 28, 32, 36, 40

6.5

8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48

6.6

6, 10, 14, 18, 22, 26, 30, 34, 38, 42

6.7

8 – 36 (even)

To participate, choose ONE of the problems listed in the Discussion Problems Column that has not already been chosen by a classmate:

1. Click the "Start a New Thread" button below the instructions to post your solution.

2. Write the section and problem number into the subject line. Example: Section 1.5 #28.

(Using this format will list the problems in order so that you can see if a problem has already been selected by a classmate.)

3. Be sure to write out the directions for the problem and the original statement of the problem then show work or an explanation with your solution; generally speaking, do not just state your answer.

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Explanation & Answer

Hey Etolo,Attached is the word file with the answers. Let me know if you want me to make any explanations or any revisions.

Assignment
Please remember to show all work on every problem.
1) Solve the equation below. Show all work following the methods discussed in class; if
an equation includes fractions, clear the fractions in the first step. If the equation has a
unique solution, please show the complete check of your answer.

5  x  7   3 7  4 x 
Solution:
5(x – 7) = -3 (7 – 4x)
5x – 5*7 = -3*7 -3*(-4x)
5x – 35 = -21 + 12x
5x – 35 – 12x = -21
5x – 12x – 35 = -21
-7x – 35 = -21
-7x = -21 + 35
-7x = 14
x = 14/(-7) = -2.
Answer: x = -2.

2) Solve the equation below. Show all work following the methods discussed in class; if
an equation includes fractions, clear the fractions in the first step. If the equation has a
unique solution, please show the complete check of your answer.

3 x  4 10  4  2 x 1  5x  3
Solutin: 3(x-4) + 10 = 4(2x-1) – (5x-3)
3x – 12 + 10 = 8x - 4 – 5x + 3
3x – 2 = 8x – 5x – 4 + 3
3x -2 – 8x = -5x – 4 + 3
-5x – 2 = -5x – 1
- 5x – 2 + 5x = -1
-5x + 5x – 2 = -1
0 – 2 = -1

-2 = -1
This is not true. So the above equation has no solution.
Answer: The above equation has no solution.

3) Solve the equation below. Show all work following the methods discussed in class; if
an equation includes fractions, clear the fractions in the first step. If the equation has a
unique solution, please show the complete check of your answer.

5 x  11  5 x  4
4 12 6 3

Solution: (5/4)x – 11/12 = (5/6)x – (4/3)
The denominators in the fractions are 4, 12, 6, and 3.
The least common multiple of these numbers is 12.
So multiplying both sides of the equation with 12 to get rid of fractions, we get:
12((5/4)x – (11/12)) = 12*((5/6)x - (4/3))
12*(5/4)x – 12*(11/12) = 12*(5/6)x - 12*(4/3)
3*5x – 11 = 2*5x – 4*4
15x – 11 = 10x – 16
15x – 11 – 10x = -16
15x – 10x – 11 = -16
5x – 11 = -16
5x = -16 + 11 = -5
5x = -5
x = -5/5 = -1.
Answer: x = -1

4) Solve the inequality below. Show all work following the methods discussed in class;
if an inequality includes fractions, clear the fractions in the first step. Write your answer
in interval notation and graph the solution set ...


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