Description
question 1 and 2
Unformatted Attachment Preview
ading
for beginners.
The interested reader may
articles by Bishop (1969, 1971), Fienberg (1970b,
18 and Larntz (1976),
Chen and Fienberg (1976), Grizzle, Starmer, and Koch (1969), Koch and Reinfurt
(1971), Grizzle and Williams (1972), Koch, Imrey, and Reinfurt (1972), Wagner
(1970), Odoroff (1970), Goodman (1971), Gart (1972), Haberman (1973), and Read
(1977). See also the book by Agresti (1990).
4.8 REVIEW PROBLEMS FOR CHAPTERS 3 AND 4
1.
men who had been separated from their biological parents since early infancy. Fifty-five
In a Danish research project to see if alcoholism is hereditary, five psychiatrists studied
had no history of alcoholism, and 4 of these 78 were alcoholic. The study found that
were found to be alcoholic. These were compared with 78 men whose biological parents
"significantly more" of the first group had a history of drinking problems. What would
your statistical analysis look like? (Associated Press, February 21, 1973.)
Prior to an election, a random sample of 200 voters were asked which candidate they
preferred. Candidate A was preferred by 85 voters, candidate B by 111 voters, and 4 voters
were undecided. How would you predict the election results? (Discuss the items that
need discussion.)
2.
3.
Several nonfreshman students at a community college were asked some questions, in-
cluding how they felt about legalizing marijuana, with the following (fictitious) re-
sults.
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Explanation & Answer
see attached
QUESTION 1:
This involves carrying out a hypothesis test for the difference in proportions.
Ho : p1 – p2 = 0
Ha: p1-p2 > 0
Phat1 = 10/55 =0.1818
Phat 2 = 4/78 = 0.0513
Z statistic =
( Phat 1− Phat 2)
𝑝1∗𝑞1 𝑝2∗𝑞2
+
𝑛1
𝑛2
√
Z=
( 0.1818− 0.0513)
0.1818∗0.8182 0.0513∗0.9487
√
+
55
78
Z= 2.42
P value = 0.0079
Since the p value is less than the significance level, we reject the null and conclude that there is a
significantly higher proportion of individuals with dri...
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