Math finance problem?

timer Asked: Dec 29th, 2012

Question description

The profit, P, that a company makes from the monthly production and sale of x tons of lawn fertilizer is given by the quadratic function: P(x)= -4x^(2)-2400x-11000; 0<x<600

I already found the max profit to be $25,000 at 300 tons of fertilizer

The domain of the function indicates that the company can produce any number of tons of fertilizer on the interval from 0 to 600, inclusive.

For any given month, the company will lose money whenever the production level is less than ___ tons or greater than ___ tons.

I already solved this graphically x<50 and 550>x

How would I set this up algebraically? 

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